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author | Alexander Lobakin <alexandr.lobakin@intel.com> | 2022-05-24 18:27:18 +0300 |
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committer | Greg Kroah-Hartman <gregkh@linuxfoundation.org> | 2022-06-14 19:32:35 +0300 |
commit | 741e49eacdcd31ec9b448a77b1ab9219a00c1db9 (patch) | |
tree | 225ab7bb45210395341ef4062c9785915c05057d /scripts/mod/modpost.c | |
parent | 42658e47f1abbbe592007d3ba303de466114d0bb (diff) | |
download | linux-741e49eacdcd31ec9b448a77b1ab9219a00c1db9.tar.xz |
modpost: fix removing numeric suffixes
[ Upstream commit b5beffa20d83c4e15306c991ffd00de0d8628338 ]
With the `-z unique-symbol` linker flag or any similar mechanism,
it is possible to trigger the following:
ERROR: modpost: "param_set_uint.0" [vmlinux] is a static EXPORT_SYMBOL
The reason is that for now the condition from remove_dot():
if (m && (s[n + m] == '.' || s[n + m] == 0))
which was designed to test if it's a dot or a '\0' after the suffix
is never satisfied.
This is due to that `s[n + m]` always points to the last digit of a
numeric suffix, not on the symbol next to it (from a custom debug
print added to modpost):
param_set_uint.0, s[n + m] is '0', s[n + m + 1] is '\0'
So it's off-by-one and was like that since 2014.
Fix this for the sake of any potential upcoming features, but don't
bother stable-backporting, as it's well hidden -- apart from that
LD flag, it can be triggered only with GCC LTO which never landed
upstream.
Fixes: fcd38ed0ff26 ("scripts: modpost: fix compilation warning")
Signed-off-by: Alexander Lobakin <alexandr.lobakin@intel.com>
Reviewed-by: Petr Mladek <pmladek@suse.com>
Signed-off-by: Masahiro Yamada <masahiroy@kernel.org>
Signed-off-by: Sasha Levin <sashal@kernel.org>
Diffstat (limited to 'scripts/mod/modpost.c')
-rw-r--r-- | scripts/mod/modpost.c | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/scripts/mod/modpost.c b/scripts/mod/modpost.c index e08f75aed429..a21aa74b4948 100644 --- a/scripts/mod/modpost.c +++ b/scripts/mod/modpost.c @@ -1982,7 +1982,7 @@ static char *remove_dot(char *s) if (n && s[n]) { size_t m = strspn(s + n + 1, "0123456789"); - if (m && (s[n + m] == '.' || s[n + m] == 0)) + if (m && (s[n + m + 1] == '.' || s[n + m + 1] == 0)) s[n] = 0; } return s; |